>>>M0N3R0 DYN4M1C 810CK 51Z3<<<
51Z3ₙ ≤ 2×Mₙ → Z3R0 P3N4L7Y.
51Z3ₙ = 1.01×Mₙ → 99.98% R3W4RD
51Z3ₙ = 10×Mₙ → 0.00 XMR D34D Z0N3
M4Xₙ = 2×M3D14N₍ₙ₋₁₀₀₎ₙ₋₁₎
R3W4RDₙ = B453 × [1 - (51Z3ₙ-Mₙ)² ÷ (10×Mₙ)²]⁺
TR4N51473:
“K33P 51Z3 ≤ 2×M3D14N → 6R48 FU11 5T4K3
G0 1% 0V3R → 1053 0.02%
G0 10× 0V3R → 6R48 0 XMR, 6TFO H0M3”
N0 H4RD C4P. N0 DR4M4. JU57 M47H 7H47 5C4135
P2P = WH47V3R 7H3 N37W0RK C4N H4NDL3
>>> 5C413 0R D13.
