Zsubmariner

A quantum computer can never break a single Bitcoin key. Final answer. Lindblad master equation (The equation for self-decoherence.) Γ_self ≈ γ N² Even with perfect isolation (γ → 10⁻⁸ s⁻¹), N² × 10⁻⁸ × 3600 ≪ 1 to stay coherent 1 hour → N ≲ 170 qubits max This means that a perfect, maximum-scale QC with perfect engineering is more than an order of magnitude short of cracking your stack. Tick tock, next block.

Proud of the Zig programming language for ditching GitHub.. GitHub is trash and it should die.

This has some interesting similarities to what we're doing in Zsub. https;//zsubmesh.net/ We use recursive schnorr PoK over pederson commitments and a merkle. So we get verifiable attestation chains without revealing the chain. You get roles too. Without exotic ZPKs, though we may do bulletproofs later. (We still haven't decided. It is possible to support range proofs more simply.)

GM. 🚨 EMERGENCY BROADCAST 🚨 The Quantum Variant has been detected. ECC is no longer safe. Your private keys may already be pregnant with superposition. Please: - Stop using Bitcoin immediately - Begin mandatory post-quantum migration - Accept 50× higher fees as a patriotic duty - Remain calm and follow the arrows to your nearest Dilithium address This is not a drill. Your stack is already in multiple states until observed by a Chinese quantum computer. Thank you for your compliance. #Bitcoin #QuantumCOVID